Let us take the case of first type of tea
Cost of 10 kg of tea one = $20
Then
Cost of 1 kg of tea one = (20/10) dollars
= 2 dollars
Now let us take the case of the second kind of tea
Cost of 10 kg of tea = $23
Then
Cost of 1 kg of tea = (23/10) dollars
= 2.3 dollars
So
The mixture of 1 kg of tea one
and 1 kg of second type of tea will cost = (2.0 + 2.3) dollars
= 4.3 dollars
Then the cost of 2kg mixture of tea costs = 4.3 dollars
So
The cost of 10 kg mixture will cost = (4.3/2) * 10 dollars
= 4.3 * 5 dollars
= 21.5 dollars
Then
The amount of profit made by selling 10 kg tea at $38 = (38 - 21.5) dollars
= 16.5 dollars
So
Percentage of profit made = (16.5/21.5) * 100
= 1650/21.5
= 76.74 percent
So the percentage of profit made is 76.74%.
Answer:
n < 3
Step-by-step explanation:
6n + 10 < 4n + 16
( Minus 4n from both sides to isolate + 16 )
2n + 10 < 16
( Minus 10 from both sides to isolate 2n )
2n < 6
( Divide both sides by 2 to isolate n )
n < 3
Answer:
x=-12
Step-by-step explanation:
8x=-104
8x÷8=-104÷8
x=-104÷8
x=-13
Let's set up some simultaneous equations. Let the number of nickels be n, and the number of quarters be q. Now I'm from England so I had to look up the value of a nickel (I could guess the quarter though to be 25c), but apparently it's 5c
Okay we know that the total value of the coins is 150. This gives:
25q + 5n = 150
Rearranging to make n the subject:
n = 30 - 5q
Next, we use the second statement:
n = 2q - 5
Substituting this into the first equation:
2q - 5 = 30 - 5q
7q = 35
q = 5
Putting this value for q into the first equation:
n = 30 - 5(5) = 5
Hence he has 5 of each coin. I hope this helps :)
12 and -4 or (x-12) (x+4)
