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Fiesta28 [93]
3 years ago
14

PLEASE HELP ME #6 Choose the graph of the solution to this inequality. *

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0

Answer:

I think it is  c

Step-by-step explanation:

hope it help

Shalnov [3]3 years ago
6 0

Answer:

D

Step-by-step explanation:

An open line is < and >

A filled line is > and equal, and < and equal

when you plug -3.5 into -6 you get 21 but when you go right, ex -3x-6 you get 18 which is less than 21

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Rosa recorded the height (in centimeters) of a pea plant over a 10-day period for a science experiment. Please help me with this
katrin [286]

Answer:

option a)

y = m(0.5) + 1.8

Step-by-step explanation:

Equation

<h3>y = mx + c</h3>

represent the equation of straight line

here m = gradient of straight line

         c = y-intercept

First find the gradient of the graph

<h3>m = y2 - y1 / x2 - x1</h3>

    = 4 - 3 / 4 - 2

    = 1 / 2

Put the values in the equation of straight line

y =mx + c

4 = 1/2(4) + c

c = 2

y = 1/2x + 2

which is approximately equal to y = 0.5x + 1.8

7 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
Assoli18 [71]

Answer:

x = 5

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 12² = 13², so

x² + 144 = 169 ( subtract 144 from both sides )

x² = 25 ( take the square root of both sides )

x = \sqrt{25} = 5

3 0
3 years ago
En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
Can someone answer this question please answer it correctly if it’s correct I will mark you brainliest
mash [69]

Answer:

Harry stains his shirt

1/5= 20%

15%

7 0
3 years ago
Read 2 more answers
A vegetable store sold 3 tons of vegetables less on the first day than on the second, and on the third day it sold 5/9 of the am
Ilya [14]
Let
x---------> <span>quantity (ton) of vegetables sold the first day
</span>y---------> quantity (ton)  of vegetables sold the second day
z---------> quantity (ton) of vegetables sold the third day

we know that
x=y-3---------> equation 1
z=(5/9)*(x+y)------> equation 2
x+y+z=98-----> equation 3
substitute equation 2 in equation 3
x+y+[(5/9)*(x+y)]=98----> multiply by 9----> 9x+9y+5x+5y=882
14x+14y=882-----> equation 4

to resolve the equations system formed by
x=y-3
14x+14y=882

using a graph tool
see the attached figure
the solution is
x=30
y=33
x+y+z=98----> z=98-(x+y)----> z=98-63---> 35

the answer is
vegetables sold the first day----> 30 ton
vegetables sold the second day----> 33 ton
vegetables sold the third day------> 35 ton

8 0
3 years ago
Read 2 more answers
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