Question

A student sets up two reactions. Reaction 1 uses 0.290 mol/L of reactant, and Reaction 2 uses 0.470 mol/L of reactant. How many times faster is Reaction 2 compared to Reaction 1?
Express your answer as a multiple of the rate for Reaction 1 to three significant figures. Note that Reaction 1 is already written for you, so just enter the number.

Answer 1

Reaction 2 will be 1.621 times faster than reaction 1

Explanation:

As the reaction 2 is taking 0.470 mol /L and reaction 1 is taking 0.290 mol /L, then the ratio of the rate of reaction will be

                   $\text { Ratio }=\frac{\text { rate of reaction } 1}{\text { rate of reaction } 2}=\frac{0.470}{0.290}=1.6207$

Asked reaction 2 how much faster than reaction 1, so rearrange the above equation, we get,            $rate of reaction 2=\frac{\text { rate of reaction } 1}{\text { ratio }}=\left(\frac{1}{1.6207}\right) rate of reaction 1$

Thus, 1.621 times reaction 2 is faster than reaction 1 as per the given question. As the reaction 2 is using more amount of reactants compared to reaction 1, the reaction 2 will be 1.6207 times faster than reaction 1.