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gavmur [86]
3 years ago
15

Figure 5 shows the expected mass of copper produced each minute

Chemistry
1 answer:
Georgia [21]3 years ago
8 0

Answer:

Answer:

Amount of heat required = 2810.5 J

Explanation:

Given data:

Mass of copper = 29.2 g

Initial temperature = 25°C

Final temperature = 275°C

Amount of heat required = ?

Solution:

Specific heat capacity of copper is 0.385 j/g.°C.

Formula:

Q = m×c×ΔT

ΔT = 275°C - 25°C

ΔT = 250°C

Q = 29.2 g × 0.385 j/g °C ×250°C

Q = 2810.5 J

Explanation:

I HOPE THIS HELPS

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Answer:

\large \boxed{\text{E) 721 K; B) 86.7 g}}

Explanation:

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\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

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V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

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\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}

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