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gavmur [86]
3 years ago
15

Figure 5 shows the expected mass of copper produced each minute

Chemistry
1 answer:
Georgia [21]3 years ago
8 0

Answer:

Answer:

Amount of heat required = 2810.5 J

Explanation:

Given data:

Mass of copper = 29.2 g

Initial temperature = 25°C

Final temperature = 275°C

Amount of heat required = ?

Solution:

Specific heat capacity of copper is 0.385 j/g.°C.

Formula:

Q = m×c×ΔT

ΔT = 275°C - 25°C

ΔT = 250°C

Q = 29.2 g × 0.385 j/g °C ×250°C

Q = 2810.5 J

Explanation:

I HOPE THIS HELPS

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Answer:

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Explanation:

It's how gravity works.

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To a 0.0001 m solution of mg(no3)2, naoh was added to a final concentration of 0.001m did a precipitate form?
Natalija [7]

I looked on a solubility chart to answer this question, and hydroxides are generally insoluble (with some exceptions of course). However, it says to consider Mg(OH)_{2} as an insoluble substance, though it may be moderately soluble.


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Mg(NO_{3})_{2}_{(aq)} + 2NaOH_{(aq)} → Mg(OH)_{2} {(s)} + 2NaNO_{3}_{(aq)}

8 0
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IceJOKER [234]
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7 0
2 years ago
An 80L capacity steel cylinder contains H2 at a pressure of 110 atm and 30 ° C, after extracting a certain amount of gas, the pr
icang [17]

Answer:

2200 L

Explanation:

Ideal gas law:

PV = nRT,

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

The initial number of moles is:

(110 atm) (80 L) = n (0.0821 L atm / K / mol) (30 + 273.15) K

n = 353.58 mol

After some gas is removed, the number of moles remaining is:

(80 atm) (80 L) = n (0.0821 L atm / K / mol) (30 + 273.15) K

n = 257.15 mol

The amount of gas removed is therefore:

n = 353.58 mol − 257.15 mol

n = 92.43 mol

At normal conditions, the volume of this gas is:

PV = nRT

(1 atm) V = (92.43 mol) (0.0821 L atm / K / mol) (273.15 K)

V = 2162.5 L

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3 years ago
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