Answer:
The area of the triangle is 18 square units.
Step-by-step explanation:
First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:
AB
![AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%285-2%29%5E%7B2%7D%2B%5B6-%28-1%29%5D%5E%7B2%7D%7D)
BC
AC
![AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%28-1-2%29%5E%7B2%7D%2B%5B4-%28-1%29%5D%5E%7B2%7D%7D)
Now we determine the area of the triangle by Heron's formula:
(1)
(2)
Where:
- Area of the triangle.
- Semiparameter.
If we know that , and , then the area of the triangle is:
The area of the triangle is 18 square units.
Answer:
The mean will increase, after the outlier is removed.
Answer:
I think the answer is undefined because the question above is an expression of f of x not a statement of variation which should have a constant of proportionality
Step-by-step explanation:
this is not an isoceles triangle.
anyway, we need to remember 2 things :
1. the sum of all angles in a triangle is always 180°.
2. the sum of all angles around a single point on a line is 360° (as this point wound be the center of an invisible circle). and as the line cuts this circle in half, the angles on one side of the line around this point is therefore 180°.
so, the internal angle Q is then
180 = 50 + 55 + Q
Q = 180 - 50 - 55 = 180 - 105 = 75°
the exterior angle x at Q is then
180 = Q + x = 75 + x
x = 180 - 75 = 105°
0.11 is the least amount.
