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3 years ago

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kayla earns a weekly salery of $290 plus a 5.5% comessin on sales at a gift shop how much would she make in a week if she sold %

5700

1 answer:

Kruka [31]3 years ago

6 0

She would make $603.50 for the week if she sold $5700.

y = 290 + 5.5%x

Where y is Kayla's total weekly salary. x is her sales for the week.

y = 290 + 5.5%(5700)
y = 290 + 313.50
y = 603.50

Kayla would earn $603.50 for the week.

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Identify the ellipses, represented by equations, whose eccentricities are less than 0.5

ozzi

Answer:

See explanation

Step-by-step explanation:

Hello, we cannot see the ellipse equations.

The eccentric of an ellipse is given by:

$e = \frac{c}{a}$

Assuming the equations are:

$\frac{ {x}^{2} }{25} + \frac{ {y}^{2} }{16} = 1$

Then a²=25 and b²=16

${c}^{2} = {a}^{2} - {b}^{2}$

${c}^{2} = 25 - 16$

${c}^{2} = {3}^{2}$

$c = 3$

The eccentricity is:

$e = \frac{3}{5} = 0.6$

If the ellipse has equation,

$\frac{ {x}^{2} }{ {5}^{2} } + \frac{ {y}^{2} }{ {3}^{2} } = 1$

then the this time, we have a=5 and b=3.

This means that:

${c}^{2} = {a}^{2} - {b}^{2}$

${c}^{2} = {5}^{2} - {3}^{2}$

${c}^{2} = {4}^{2}$

$c = 4$

$c = \frac{4}{5} = 0.8$

3 0

3 years ago

Read 2 more answers

An automobile dealer wants to see if there is a relationship between monthly sales and the interest rate. A random sample of 4 m

SVETLANKA909090 [29]

Answer:

a) $y=-6.254 x +75.064$

b) r =-0.932

The % of variation is given by the determination coefficient given by $r^2$ and on this case $-0.932^2 =0.8687$ , so then the % of variation explained by the linear model is 86.87%.

Step-by-step explanation:

Assuming the following dataset:

Monthly Sales (Y) Interest Rate (X)

22 9.2

20 7.6

10 10.4

45 5.3

Part a

And we want a linear model on this way y=mx+b, where m represent the slope and b the intercept. In order to find the slope we have this formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=278.65-\frac{32.5^2}{4}=14.5875$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=696.9-\frac{32.5*97}{4}=-91.225$

And the slope would be:

$m=\frac{-91.225}{14.5875}=-6.254$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{32.5}{4}=8.125$

$\bar y= \frac{\sum y_i}{n}=\frac{97}{4}=24.25$

And we can find the intercept using this:

$b=\bar y -m \bar x=24.25-(-6.254*8.125)=75.064$

So the line would be given by:

$y=-6.254 x +75.064$

Part b

For this case we need to calculate the correlation coefficient given by:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

$r=\frac{4(696.9)-(32.5)(97)}{\sqrt{[4(278.65) -(32.5)^2][4(3009) -(97)^2]}}=-0.937$

So then the correlation coefficient would be r =-0.932

The % of variation is given by the determination coefficient given by $r^2$ and on this case $-0.932^2 =0.8687$ , so then the % of variation explained by the linear model is 86.87%.

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Answer:

28

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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