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3 years ago

6

A cylinder can hold 450 inches of water. How many cubic inches of water can a cone that has a congruent base and equal height to

the cylinder hold?

1 answer:

Paladinen [302]3 years ago

7 0

Answer:

150 cubic inches of water

Step-by-step explanation:

volume of a cylinder = πr²h

Volume of a cone 1/3(πr²h)

π = 22/7

r = radius

volume of a cone = $\frac{1}{3}$ x Volume of a cylinder

450 / 3 = 150 in³

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suppose we want to choose 5 letters, without replacement, from 13 distinct letters. (a) how many ways can this be done, if the o

CaHeK987 [17]

A. The number of possible ways can this be done, if the order of the choices is not taken into consideration is 1, 287 ways

B. The number of possible ways can this be done, if the order of the choices is taken into consideration is 154,440 ways

<h3>What is meant by permutation and combination?</h3>

Combination and permutation are two alternative strategies in mathematics to divide up a collection of components into subsets. The subset's components can be listed in any order when combined. The components of the subset are listed in a permutation in a certain order.

A. We want to select 5 objects from a total 13, without considering the order in which they are chosen.

The correct way to do this exists by utilizing the combination formula since order exists not considered;

Therefore, we have ; 13 C 5 read as 13 combination 5;

Let the equation of combination be n C r = n!/(n-r)!r!

substituting the values in the above equation, we get

13!/(13-8)!8! = 13!/5!8! = 1,287 ways

B. By considering order, we shall be using the permutation formula;

Let the equation of permutation be n P r = n!/(n-r)!

substituting the values in the above equation, we get

13 P 5 = 13!/(13-5)!

= 13!/(13-5)! = 13!/8! = 154,440 ways

To learn more about permutation and combination refer to:

brainly.com/question/11732255

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3 0

1 year ago

Juan Jiménez le debe a Luis $15, a José le debe $ 8 y a Dana $ 20 y a Juan Jiménez le debe $ 17 Ana, $ 5 Daniela y $ 21 Pedro.

Lapatulllka [165]

Answer :

Los dos debe y le deben porgue son diffirentes personas. Cuando le pagen los tres Ana, 'daniela y Pedro puede pagarle a Luis, Jose y Juan

Step-by-step explanation:

Juan debe un total de $43 a Luis, Jose y Juan

Ana, Daniela y Pedro le deben a Juan un total de $43

5 0

3 years ago

C and D are mutually exclusive events. Find P(C or D).<br> P(C)= 3/7= P(D)= 4/7<br> P(C or D)

IgorLugansk [536]

Answer:

$P(C\ or\ D) = 1$

Step-by-step explanation:

Given

$P(C) = \frac{3}{7}$

$P(D) = \frac{4}{7}$

Required

$P(C\ or\ D)$

Since the events are mutually exclusive, then:

$P(C\ or\ D) = P(C) + P(D)$

So, we have:

$P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}$

Take LCM

$P(C\ or\ D) = \frac{3+4}{7}$

$P(C\ or\ D) = \frac{7}{7}$

$P(C\ or\ D) = 1$

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3 years ago

In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the pr

yanalaym [24]

Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = $\frac{13}{71}$

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = $\frac{13-1}{71-1}$ = $\frac{12}{70}$

what is the probability that none of the 2 vials have hairline cracks.

i.e $(\frac{13}{71}) * (\frac{12}{70})$

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313

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3 years ago

You push a coin across a table. The coin stops how does the motion relate to the balance and unbalanced forces

Wewaii [24]

When it is in motion the force is unbalanced. When it stops the forces are balanced.

6 0

3 years ago

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