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icang [17]
3 years ago
6

To prove that objects of different weights fall at the same

Mathematics
1 answer:
enot [183]3 years ago
6 0

Answer:

y = 1609 ft

Step-by-step explanation:

g is equal to 9,8 m/s²     or 32,18 ft/s²

According to g = 32,18 ft/s²

In the first second      as  y = -1/2 g*t²

y  = 1/2 32,18*(1)²       ⇒  y  = 16,9 ft           we dismiss the sign we know the object is falling down. Is enough for the purpose of this question

The second one

y  = 1/2* (32,18)* (2)²

y = 32,18*2          ⇒    y = 64,36 ft

third second

y = 1/2*32,18*(3)²     ⇒  y  = 144,81 ft

And in the  tenth second

y =( 1/2)* 32,18 * (10)²      ⇒    y = 1609 ft

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Answer:

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General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Point (40, 3000)

Point (60, 4000)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{4000-3000}{60-40}
  2. Subtract:                       m=\frac{1000}{20}
  3. Divide:                          m=50
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