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3 years ago

Can i get answers pllzzzz

Mathematics

1 answer:

BabaBlast [244]3 years ago

5 0

Answer:

C jsdjdjrishbxcbdjwiausus sorry I need to put the 20 words or.morrr

it's C

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Solve 3^(x − 2) = 37. A 2 B 5 C 7 D 9

ASHA 777 [7]

Answer:

Step-by-step explanation:

$3^{x-2}=3^7\iff x-2=7\qquad\text{add 2 to both sides}\\\\x-2+2=7+2\\\\x=9$

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3 years ago

The sixth-graders at Kate's school got to choose between a field trip to a museum and a field trip to a factory. 19 sixth-grader

amm1812

25% because 19+57= a total of 76 students and the percentage of 19 out of 76 is 25%.

19/76= 0.25

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3 years ago

The math club and the science club held fundraisers to buy supplies for a local shelter. The science club spent $110 buying four

VashaNatasha [74]

$27.5 for each case of water
$17.91 for each case of juice

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3 years ago

a speed skater completes a 500 meter race in 40 seconds. A cheetah runs 260 meters in 10 seconds. How do their speeds compare?

puteri [66]

Answer:

Skater 500 m / 40 sec = 12.5 m/ sec

Cheetah 260 / 10 = 26 m/ sec

The cheetah is more than twice as fast as the skater.

Step-by-step explanation:

8 0

4 years ago

VERY EASY PLZ ANSWER.....Robert and Tony love to read. Robert reads 30 pages on the first day and 20 pages each day after that.

ivolga24 [154]

Answer:

The first graph (see figure attached)

Explanation:

1. Number of pages read by Robert

Set a function for the number of pages read by Robert, taking into account that this is an arithmetic sequence, whose first term is 30, and the common difference is 20:

$a_n=a_0+d(n-1)$

R(n) = 30 + 20 (n - 1)

↑ ↑ ↑

first day next days

2. Number of pages read by Tony:

The arithmetic sequence that represents the number of pages read by Tony has first term 40, and common difference 14:

$a_n=a_0+d(n-1)$

T(n) = 40 + 15 (n - 1)

↑ ↑ ↑

first day next days

3. Find the numbers of pages read by Tony in terms of the number of pages read by Robert.

To do that, you must clear n from both equations and equal the two expressions obtained:

From R(n) = 30 + 20 (n - 1):

R(n) = 30 + 20n - 20
R(n) = 10 + 20n
n = [R(n) - 10]/20

You can change R(n) to r:

n = (r - 10) / 20

From T(n) = 40 + 15 (n - 1)

T(n) = 40 + 15n - 15

T(n) = 25 + 15n

n = [T(n) - 25]/15

Change T(n) to t

n = (t - 25)/15

Equal both expressions:

(r - 10) / 20 = (t - 25)/15

Solve for t:

15(r-10) = 20(t - 25)

15r - 150 = 20t - 500

15r - 150 + 500 = 20t

15r + 350 = 20t

3r + 70 = 4t

4t = 3r + 70

t = (3/4)r + 70/4

t = 0.75r + 17.5

Find some points of the equation t = 0.75r - 17.5 to compare with the points of the graph:

r = 0 ⇒ t = 17.5, that means that the line intercepts the vertical axis at 17.5. The only graph that matches this is the first graph

Find other point:

r = 30 ⇒ t = 0.75(30) + 17.5 = 40.Thus, the graph must contain the point (30, 40), which the first graph does.

3 0

3 years ago