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alisha [4.7K]
3 years ago
15

Please help ! Will mark brainliest!

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

$8

Step-by-step explanation:

if he works overtime for ten hours and earned $120 he makes $12 overtime pay. If you divide that by time and a half it's 8

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For this exponential function what is the output value (y) when the input value (x) is 0?
Alenkinab [10]

Answer:

12

Step-by-step explanation:

y^0=1\\5^0=1\\12*1=12

6 0
3 years ago
The width of the rectangle is 0.6 meters less than the length. The perimeter of a rectangle is 60.8 meters. Find the dimensions
Anvisha [2.4K]

Answer:

14+=+2L+%2B+2%28L-3%29 Simplify and solve for L

14+=+2L+%2B+2L+-+6 Combine like-terms.

14+=+4L-6 Add 6 to both sides.

20+=+4L Divide both sides by 4.

5+=+L The length is 5 meters.

W+=+L-3

W+=+5-3

W+=+2meters.

The width is 2 meters.

P+=+2L%2B2W

P+=+2%285%29%2B2%282%29

P+=+10%2B4

P+=+14meters.

Step-by-step explanation:

4 0
3 years ago
Alex made an eyeglass case and sold it for $12.00. He spent $1.29 on felt and $2.75 on a needle and thread. What was his profit?
madreJ [45]
D because 1.29 plus 2.75 is 4.04(the money that he used to make the case) and subtract that with $12 and you get $7.96 as the profit.
5 0
3 years ago
Read 2 more answers
Approximate the value of 13√ to the nearest tenths place. Plot the approximation on the number line.
aalyn [17]
The square root of 13 rounded to the nearest tenth is 3.6, so you would plot this somewhere in between 3 and 4 on a number line.
4 0
3 years ago
Read 2 more answers
Find a polynomial function of degree 3 with 2, i, -i as zeros.
sergiy2304 [10]

Answer:

p(x)= x^3-2x^2+x-2

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if \alpha , \ \beta \ \& \ \gamma are the zeros of the cubic polynomial , then ,

\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)

Here in place of the Greek letters , substitute 2,i and -i , we get ,

\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

\sf  \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}

Simplify using i = √-1 ,

\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )

Multiply by distribution ,

\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)

Simplify by opening the brackets ,

\sf\longrightarrow p(x)= x^3+x-2x^2-2

Rearrange ,

\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}

4 0
2 years ago
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