Answer:
F(1) represents the first term of the sequence.
Step-by-step explanation:
Let us suppose the sequence function
![F(n) = 16-3n](https://tex.z-dn.net/?f=F%28n%29%20%3D%2016-3n)
We can find the first term of the sequence by substituting n=1 in the function sequence
![F(1) = 16-3(1)](https://tex.z-dn.net/?f=F%281%29%20%3D%2016-3%281%29)
![= 16-3](https://tex.z-dn.net/?f=%3D%2016-3)
![=13](https://tex.z-dn.net/?f=%3D13)
We can find the 2nd term of the sequence by substituting n=2 in the function sequence
![F(2) = 16-3(2)](https://tex.z-dn.net/?f=F%282%29%20%3D%2016-3%282%29)
![= 16-6](https://tex.z-dn.net/?f=%3D%2016-6)
![=10](https://tex.z-dn.net/?f=%3D10)
We can find the 3rd term of the sequence by substituting n=3 in the function sequence
![F(3) = 16-3(3)](https://tex.z-dn.net/?f=F%283%29%20%3D%2016-3%283%29)
![= 16-9](https://tex.z-dn.net/?f=%3D%2016-9)
![=7](https://tex.z-dn.net/?f=%3D7)
So the first three terms of the sequence is:
13, 10, 7...
As the common difference is the same.
i.e. d = 10-13 = -3, d = 7-10 = -3
Hence, it is an Arithmetic sequence.
As the first term is 13, which can be obtained by putting n=1 in the function sequence.
Therefore, from the above discussion, we can conclude that F(1) represents the first term of the sequence.