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3 years ago

How do i get the answer x= 3, -1 for equation (3/x^2)+ 2/x =1

Mathematics

1 answer:

Assoli18 [71]3 years ago

3 0

Answer:

Steps below

Step-by-step explanation:

(3/x²)+ 2/x =1 (x ≠ 0)

(3/x²) + 2x/x² = 1

(3 + 2x) / x² = 1

3 + 2x = x²

x² - 2x - 3 = 0

(x + 1) (x - 3) =0

x = -1 or x = 3

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3 years ago

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nikklg [1K]

Answer:

$\displaystyle m=-2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
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Left to Right

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Step-by-step explanation:

Step 1: Define

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Point (-1, 8)

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2 years ago

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olchik [2.2K]

Answer:

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Step-by-step explanation:

Given vector field,

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Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

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$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

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$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$

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