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3 years ago

How does the circular flow model help people see the error in believing there is a fixed lump of labor?

1 answer:

4 0

B. Adding new people into the model means that there are more films and production increases. So, there are more goods and services, but not more households.

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The changes in account balances of the Vel Corporation during Year 6 are presented below: Increase Assets $356,000 Liabilities 1

zzz [600]

Answer:

b. $ 36,000

Explanation:

The fundamental accounting equation is

Assets = Liabilities + Stockholders Equity

Per the data provided in the question regarding changes in account balances

$ 356,000 = $108,000 + (240,000+24,000)

$ 356,000 = $ 372,000

= - ($ 14,000)

Since the data provides that a dividend payment of $ 52,000 has been made, we have to add it to our differential balance to get the income for the year.

$ - 14,000 + $ 52,000 = $ 36,000

6 0

3 years ago

What course of action does a party to a contract have if the other party is found to be in breach of that contract?

taurus [48]

Damages for breach, reasonable attorney fees and costs are the course of action which a party in contract would have.

<h3><u>What is attorney fees?</u></h3>

Attorney's fee is a term used mostly in the United States to describe payment for legal services rendered for a client, whether in or out of court.
It could be a flat-rate, hourly, or contingent charge.
According to recent studies, lawyers who charge flat fees as opposed to hourly rates put in less effort for their clients and produce worse results. In a court case, attorney fees are distinct from fines, compensatory and punitive damages, and (apart from in Nevada) from court costs.

According to the "American norm," unless there are special statutory or contractual rights, the losing party in a dispute often does not pay the winning side's legal fees.

Know more about attorney fees with the help of the given link:

brainly.com/question/27960792

#SPJ4

6 0

2 years ago

Solve the exponential equation by taking the logarithm on both sides. 5^(x+8)=7

rodikova [14]

<h2>Answer:</h2>

x = (log₅7) - 8

<h2>Explanation:</h2>

<em>Given;</em>

$5^{x+8}$ = 7

<em>Take log of both sides;</em>

log₁₀( $5^{x+8}$ ) = log₁₀7 -------------(ii)

<em>From the laws of logarithm remember that;</em>

logₐ xⁿ = n logₐ x

<em>Equation (ii) can then be written as;</em>

(x + 8)log₁₀5 = log₁₀7

<em>Divide both sides by log₁₀5</em>

(x + 8) = $\frac{log_{10}7}{log_{10}5}$ -----------(iii)

<em>From the laws of logarithm, remember that;</em>

$\frac{log_{a}x}{log_{a}y} = log_yx$

<em>Equation (iii) can thus be written as;</em>

(x + 8) = log₅7

x + 8 = log₅7

<em>Make x subject of the formula;</em>

x = (log₅7) - 8

7 0

3 years ago

Your friend Jeanne is searching for a job and has decided to update her LinkedIn profile. She wants to enhance the credibility o

Vadim26 [7]

I would suggest she’d ask for recommendations from instructors, employers, and colleagues.

7 0

3 years ago

If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func

ANTONII [103]

Answer:

Following are the solution to the question:

Explanation:

Calculating the total cost:

$C(x) = 2,000 + 140x + \frac{4x^3}{2}$

Calculating the marginal cost:

$M(x) = C'(x) = 140 + 6 \times \frac{1}{2}$

Calculating the average cost:

$A( x ) =\frac{ C( x )}{x} = 2,000x-1 + 140 + 4\times \frac{1}{2}$

Calculating the marginal average cost:

$m( x ) = A'( x ) = -2,000x-2 + 2x-\frac{1}{2}$

In point (a)

$C( 1,000 )$

$= 2,000 + 140( 1,000 ) + 4( 1,000)^{\frac{3}{2}}\\\\= \$ \ 268,491.106 \\\\ = \$ \ 268,491.11$

In point(b)

$A( 1,000 )$

$= 2,000( 1,000 )-1 + 140 + 4( 1,000 )^{\frac{1 }{2}}\\\\= \frac{\$ \ 268.491106} {unit}\\\\= \frac{\$ \ 268.49}{ unit}$

In point (c)

$M( 1,000)$

$= 140 + 6( 1,000 )^{\frac{1}{2}}\\\\= \frac{\$ \ 329.73666}{unit}\\\\= \frac{ \$ \ 329.74}{ unit}$

In point (d)

Calculating the average cost:

$A'( x ) = m( x ) = -2,000x-2 + 2x- \frac{1}{2}\\\\A'( x ) = 0 = -2,000x-2 + 2x-\frac{1}{2}= 0\\\\multiply \ by \ 2\\\\\to -2,000 + 2 \times \frac{x^3}{2}= 0 \\\\\to 2\times \frac{x^3}{2} = 2,000 \\\\\to \frac{x^3}{2} = \frac{2,000}{2} \\\\ \to \frac{x^3}{2}= 1,000 \\\\\to x = ( 1,000 )^{\frac{2}{3}}\\\\ \to 100 \ units$

In point (e)

$A( 100 )$

$= 2,000( 100 )-1 + 140 + 4( 100 )^{\frac{1}{2}}\\\\= \frac{ \$ \ 200}{unit}$

6 0

3 years ago