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barxatty [35]
3 years ago
7

An article bought for Rs1000 is sold in fourth-fift of the cost prize . What is the profit percentage?

Mathematics
1 answer:
adoni [48]3 years ago
4 0

Answer:

-20%

Step-by-step explanation:

Given that :

Purchase price = Rs1000

Price sold = 4/5 of the purchase price

Price sold = 4/5 * 1000 = Rs. 800

Profit Percentage :

(price sold - purchase price) / purchase price * 100%

(800 - 1000) / 1000 * 100%

(-200 / 1000) * 100%

-0.2 * 100%

-20%

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For a person who has a mass 60 kg , calculate the weight in Newton if 1 In equals 4.45 N , then what is the person's weight in p
wel

Answer:

The answer to your question is  a) 588.6 N   b) 132.3 N

Step-by-step explanation:

Data

mass = 60 kg

weight = ?

Process

1.- Write the formula of weight

     Weight = mass x gravity

gravity = 9.81 m/s²

2.- Substitution

     Weight = 60 x 9.81

3.- Result

     Weight = 588.6 kg m/s² = 588.6 N

4.- Convert Newtons to Pounds

                     1 pound -----------  4.45 N

                     x            ----------- 588.6 N

                     x = (588.6 x 1) / 4.45

                     x = 132.3 pounds

4 0
4 years ago
Perform the indicated operation. x/2+y/3-z/4
weeeeeb [17]

\bf \cfrac{x}{2}+\cfrac{y}{3}-\cfrac{z}{4}\implies \stackrel{\textit{using the LCD of 12}}{\cfrac{(6)x~~+~~(4)y~~-~~(3)z}{12}}\implies \cfrac{6x+4y-3z}{12}

3 0
3 years ago
Read 2 more answers
Slope = 4/3, (-2, 11)
Lady_Fox [76]

Answer:

y = \frac{4}{3} x + \frac{41}{3}

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

here m = \frac{4}{3}, hence

y = \frac{4}{3} x + c ← is the partial equation

to find c substitute (- 2, 11) into the partial equation

11 = - \frac{8}{3} + c ⇒ c = \frac{41}{3}

y = \frac{4}{3} x + \frac{41}{3} ← equation of line


7 0
3 years ago
1. D=5.9 ft.
Shtirlitz [24]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

\qquad \sf  \dashrightarrow \:c =  \pi d

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

\qquad \sf  \dashrightarrow \:c =  2\pi r

Now, let's move on to questions ~

<h3>First </h3>

\qquad \sf  \dashrightarrow \:3.14 \times 5.9

\qquad \sf  \dashrightarrow \: \approx18.53 \: ft

<h3 />

・ .━━━━━━━†━━━━━━━━━.・

<h3>Second</h3><h3 /><h3 /><h3 /><h3>\qquad \sf  \dashrightarrow \:3.14 \times 3.2</h3>

\qquad \sf  \dashrightarrow \: \approx10.048 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Third</h3>

\qquad \sf  \dashrightarrow \:3.14 \times 6.1

\qquad \sf  \dashrightarrow \: \approx19.15 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fourth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  3.7

\qquad \sf  \dashrightarrow \: \approx2×11.62  \: m

\qquad \sf  \dashrightarrow \: \approx23.24  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fifth </h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  6.2

\qquad \sf  \dashrightarrow \: \approx2× 19.47 \: units

\qquad \sf  \dashrightarrow \: \approx38.94  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Sixth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  5.1

\qquad \sf  \dashrightarrow \: \approx2×16.01 \: ft

\qquad \sf  \dashrightarrow \: \approx \: 32.02m

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

7 0
2 years ago
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Aliun [14]
《ANSWER》

《LINEAR EQUATIONS》

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only one solution

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Only one solution

↪5) 6 (x + 5) = 6x + 11

NO SOLUTION

All the equations are solved by the distributive law of algebra
5 0
3 years ago
Read 2 more answers
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