Is this the original question or?
Answer:
160
Step-by-step explanation:
had the question before
When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
The equation of line with given points and perpendicular to y-axis is
y = - 7
Step-by-step explanation:
Given as :
The given points as ( - 10 , - 7)
The equation of line is Y = mX + c
So The line will satisfy given points
Or, - 7 = m ( -10 ) + c
Now This line is perpendicular to y- axis
∴ The slop of line perpendicular to y axis is 0
So, - 7= 0 + c
or, c = - 7
∴ Equation of line is y = 0 + c
Or, y = - 7
Hence The equation of line with given points and perpendicular to y-axis is y = - 7 Answer
