Write an equation of the line that passes through the points (−3,−4) and (0,2).

Mathematics

2 answers:

blsea [12.9K]3 years ago

6 0

Y+0=23(x+3) is the answer to that question

Leno4ka [110]3 years ago

4 0

It should be y=2x+2 it has to be in slope form: y=mx+b

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Zina [86]

For this case we must solve the following quadratic equation:

$3x ^ 2-2x + 5 = 0$

Where:

$a = 3\\b = -2\\c = 5$

The roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values we have:

$x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (3) (5)}} {2 (3)}\\x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (3) (5)}} {2 (3)}\\x = \frac {2 \pm \sqrt {4-60}} {6}\\x = \frac {2 \pm \sqrt {-56}} {6}$

By definition we have to:

$i ^ 2 = -1\\x = \frac {2 \pm \sqrt {56i ^ 2}} {6}\\x = \frac {2 \pm i \sqrt {56}} {6}\\x = \frac {2 \pm i \sqrt {2 ^ 2 * 14}} {6}\\x = \frac {2 \pm 2i \sqrt {14}} {6}\\x = \frac {1 \pm i \sqrt {14}} {3}$