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3 years ago

Please help will give brainliest.

Mathematics

1 answer:

Olenka [21]3 years ago

4 0

-1/7 is the correct answer for slope

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Find the midpoint rounded to the nearest hundreth a (-2,1) b (-1,1)

Veronika [31]

Answer:

$(-1.5, 1)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

Endpoint A (-2, 1)

Endpoint B (-1, 1)

Step 2: Find Midpoint

Simply plug in your coordinates into the midpoint formula to find midpoint

Substitute [MF]: $(\frac{-2-1}{2},\frac{1+1}{2})$
Subtract/Add: $(\frac{-3}{2},\frac{2}{2})$
Divide: $(-1.5, 1)$

8 0

3 years ago

What is the x-intercept of the graph of 3x + 12 = -6?

Sever21 [200]

Answer:

x=−6

Step-by-step explanation:

6 0

3 years ago

Which of the following expressions is a polynomial?

Assoli18 [71]

Hello from MrBillDoesMath!

Answer:

The second choice

Discussion:

The first choice is not a polynomial because it contains sqrt(x)

The third choice is not a polynomial because it contains (1/x)

The fourth choice is not a polynomial because it contains x in the exponent (ie. 5^x)

Thank you,

MrB

4 0

3 years ago

305 to the nearest ten

HACTEHA [7]

305 to the nearest ten is 310.

5 0

3 years ago

Read 2 more answers

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Solution:

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago