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Luden [163]
3 years ago
9

What is the measure of the indicated missing angle? Help I will mark brainliest

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

approximately 38.42

Step-by-step explanation:

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Zachary created a garden that measured7 x 6.5 feet. How many 8-foot rolls of fencing will he need to completely surround the gar
lutik1710 [3]

Answer:

6 rolls

Step-by-step explanation:

7 × 6.5 is 45.5

45.5 ÷ 8 is 5.6875

5.6875≈6

So 6!

8 0
3 years ago
Solve the equation: log4(x + 20) = 3
Angelina_Jolie [31]
Loga x=n    ⇔a^n=x
Therefore:

log₄ (x+20)=3
3⁴=x+20
64=x+20
x=64-20
x=44

Answer: x=44
6 0
3 years ago
Read 2 more answers
The sum of four consecutive integers is 134. Find the integers. (please show your work)
lidiya [134]

Answer:

Integers: 32,33,34,35

Step-by-step explanation:

Consecutive means back-to-back, with a difference of 1

Therefore this can be represented with the following equation (where x is the first number), and we can set this equal to the sum

x+(x+1)+(x+2)+(x+3)=134\\4x+6=134\\4x=128\\x=32

Therefore since x = 32, all four integers are:

32,33,34,35

If we check this, we can see that their sum equals to 134

32+33+34+35 = 134

Hope this helps!

8 0
3 years ago
Compute the second partial derivatives ∂2f ∂x2 , ∂2f ∂x ∂y , ∂2f ∂y ∂x , ∂2f ∂y2 for the following function. f(x, y) = 2xy (x2 +
blsea [12.9K]

Answer with step-by-step explanation:

We are given that a function

f(x,y)=2xy(x^2+y^2)^2

Differentiate partially w.r.t x

Then, we get

\frac{\delta f}{\delta x}=2y(x^2+y^2)^2+8x^2y(x^2+y^2)=(x^2+y^2)(2x^2y+2y^3+8x^2y)=2(5x^2y+y^3)(x^2+y^2)

Differentiate again w.r.t x

\frac{\delta^2f}{\delta x^2}=2(10xy)(x^2+y^2)+4x(5x^2y+y^3)=20x^3y+20xy^3+20x^3y+4xy^3=40x^3y+24xy^3

Differentiate function w.r.t y

\frac{\delta f}{\delta y}=2x(x^2+y^2)^2+2xy\times 2(x^2+y^2)\times 2y

\frac{\delta f}{\delta y}=(x^2+y^2)(2x^3+2xy^2+8xy^2)=2(x^2+y^2)(x^3+5xy^2)

Again differentiate w.r.t y

\frac{\delta^2f}{\delta x^2}=2(2y)(x^3+5xy^2)+20xy(x^2+y^2)=4x^3y+20xy^3+20x^3y+20xy^3=24x^3y+40xy^3

Differentiate partially w.r.t y

\frac{\delta^2f}{\delta y\delta x}=2(2y(5x^2y+y^3)+(x^2+y^2)(5x^2+3y^2))=10x^4+36x^2y^2+10y^4

\frac{\delta^2f}{\delta y\delta x}=10x^4+36x^2y^2+10y^4\frac{\delta^2f}{\delta x\delat y}=2(2x(x^3+5xy^2)+(3x^2+5y^2)(x^2+y^2))=10x^4+36x^2y^2+10y^4

\frac{\delta^2f}{\delta x\delat y}=10x^4+36x^2y^2+10y^4

Hence, if f(x,y) is of class C^2 (is twice continuously differentiable), then the mixed partial derivatives are equal.

i.e\frac{\delta^2f}{\delta y\delta x}=\frac{\delta^2f}{\delta x\delta y}

8 0
4 years ago
NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS PLZ
Mumz [18]

Answer:

Step-by-step explanation:

Choice A

Log 10 = 1.

So A is actually right, although it does not look it.

log(20 * x^5 ) - 1   is correct.

Choice B

Log(x^5 * 20 / 10)

log(2 x^5)  

Choice B is also correct

Choice C is not correct, or if it is, I don't know how to get it. You need the 20 in there somewhere.

No! Dis not correct. The 2 is not raised to the 5th power.

And E is not correct.  I'm not sure how they got it. Even + 1 is not correct. It should be -1 if that is how it is to be done.

6 0
3 years ago
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