1+3+5+7+...+999 =
= 1+2+3+4+...+500
+1+2+3+...+499
= 2·(1+2+3+...+499) + 500
= 2·(499·500)/2 + 500
= 499·500 + 500
= 500·(499 + 1)
= 500·500
= 250.000
Answer:
Step-by-step explanation:
3x > 15 2x > 12 x + 1 < 8 7x < 42
/3 /3 /2 /2 -1 -1 /7 /7
x > 5 x > 6 x < 7 x < 6
Answer:
It's on ur most recent version of this question
First you have to isolate one of the equations for y=mx+b.
Then substitute the equation is made into the first equation
