Answer:
$15.6
Step-by-step explanation:
First, let's assume that <em>x</em> is the total money in the bag of coins.
1. <em>x</em> = total money
4/13 of the coins are pennies, so 4/13 of x equals to the number of pennies.
4/13(x) = P (pennies)
What is left that is not pennies is 9/13(x). And out of these, 1/4 are nickels. Which means:
1/4(9/13[x]) = N (nickels)
If 1/4 of the remaining are nickels, then 3/4 are dimes. So:
3/4(9/13[x]) = $8.10 (dimes' value)
After calculating the one with the value:
27/52(x) = $8.10
27x = $8.10 times 52
x = ($8.10 times 52)/27
x = 52 x $0.3
x = $15.6
Ans. The value of the bag of coins is $15.6
Answer:
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You can take like 557divided by 59
As your testing H0:p=0.79, then you have a two-tailed test.
The p-value at two-tailed test is given by:
Then, you need to check into the standard normal cumulative table to find at which -z you do have a probability of 0.395. Thus:
As you can see in the picture at z=-0.26 you have a P(Z<=-z)=0.3974
And at z=-0.27 you have a P(Z<=-z)=0.3936.
The average of these values is:
Then, you have a probability of 0.395 at a z of:
Then -z=-0.27, thus z=0.27
1. x greater than or equal to 4 (B)
2. x does not equal 4 (C)
3. A
4. B
5. B
6. A
7. B
8. C
(The pictures were out of order but i did it by number shown in the pictures. Hope this helps.)
