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Aneli [31]
2 years ago
12

A person has a bag of coins.

Mathematics
2 answers:
lbvjy [14]2 years ago
8 0

Answer:

$15.6

Step-by-step explanation:

First, let's assume that <em>x</em> is the total money in the bag of coins.

1. <em>x</em> = total money

4/13 of the coins are pennies, so 4/13 of x equals to the number of pennies.

4/13(x) = P (pennies)

What is left that is not pennies is 9/13(x). And out of these, 1/4 are nickels. Which means:

1/4(9/13[x]) = N (nickels)

If 1/4 of the remaining are nickels, then 3/4 are dimes. So:

3/4(9/13[x]) = $8.10 (dimes' value)

After calculating the one with the value:

27/52(x) = $8.10

27x = $8.10 times 52

x = ($8.10 times 52)/27

x = 52 x $0.3

x = $15.6

Ans. The value of the bag of coins is $15.6

Y_Kistochka [10]2 years ago
5 0
The answer is $15.06
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You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us
Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that    

step 1

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

r=10\%=10/100=0.10\\n=4  

substitute in the formula above

A=P(1+\frac{0.10}{4})^{4t}  

A=P(1.025)^{4t}  

Applying property of exponents

A=P[(1.025)^{4}]^{t}  

A=P(1.1038)^{t}  

step 2

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

r=10\%=10/100=0.10  

substitute in the formula above

A=P(e)^{0.10t}  

Applying property of exponents

A=P[(e)^{0.10}]^{t}  

A=P(1.1052)^{t}  

step 3

Compare the final amount

P(1.1052)^{t} > P(1.1038)^{t}

therefore

Find the difference

P(1.1052)^{t} - P(1.1038)^{t} ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0
3 years ago
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