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yaroslaw [1]
3 years ago
6

(34 - 6) =(24-1) is...?

Mathematics
1 answer:
Alex3 years ago
4 0

Answer:

34-6 and 24-1 are not equal to each other

Step-by-step explanation:

(34-6)=(24-1)

28 is not equal to 23

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E. What order will result in a final output of 36 when the initial input is 1/7?
natima [27]

Answer:

5

Step-by-step explanation:

7x5=35

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the nearest number is 5

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2 years ago
Zach paid $40.09,including sales tax,for a book priced at $38.00. What was the sales tax rate?a.5%b.5.25%c.5.5%d.6%
Ivahew [28]

Answer: 5.5%

Step-by-step explanation: 5.5% of 38% is $2.09 adding it to $38.00 makes its $40.09

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2 years ago
QUICK PLEASE!
AleksAgata [21]

Answer:

1, 3, 4, 5 and 6

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Choose the correct problem formulation: Hotels, like airlines, often overbook, counting on the fact that some people with reserv
Marina CMI [18]

Answer:

P(8 < x \leq 12)=P(X=9)+P(X=10)+P(X=11)+P(X=12)

P(X=9)=(15C9)(0.8)^{9} (1-0.8)^{15-9}=0.0429

P(X=10)=(15C10)(0.8)^{10} (1-0.8)^{15-10}=0.1032

P(X=11)=(15C11)(0.8)^{11} (1-0.8)^{15-11}=0.1878

P(X=12)=(15C12)(0.8)^{12} (1-0.8)^{15-12}=0.2501

P(8 < x \leq 12)=0.0429+0.1032+0.1878 +0.2501=0.5839

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=15, p=1-0.2=0.8)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(8 < x \leq 12)=P(X=9)+P(X=10)+P(X=11)+P(X=12)

P(X=9)=(15C9)(0.8)^{9} (1-0.8)^{15-9}=0.0429

P(X=10)=(15C10)(0.8)^{10} (1-0.8)^{15-10}=0.1032

P(X=11)=(15C11)(0.8)^{11} (1-0.8)^{15-11}=0.1878

P(X=12)=(15C12)(0.8)^{12} (1-0.8)^{15-12}=0.2501

P(8 < x \leq 12)=0.0429+0.1032+0.1878 +0.2501=0.5839

7 0
3 years ago
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