Simplify the following:
(-6 (-8)×2×3 x x x x)/(3×4)
(8 x×2 x (-6) x×3 x (-1))/(3×4) = (8 x^4×2 (-6)×3 (-1))/(3×4):
(-6 (-8)×2×3 x^4)/(3×4)
8×2 = 16:
(-6 (-3)16 x^4)/(3×4)
16 (-6) = -96:
(-3-96 x^4)/(3×4)
-96 (-3) = 288:
(288 x^4)/(3×4)
3×4 = 12:
(288 x^4)/12
|
1 | 2 | | 2 | 4
| 2 | 8 | 8
- | 2 | 4 |
| | 4 | 8
| - | 4 | 8
| | | 0:
Answer: 24 x^4
Here you go! I’m not sure if they want it in decimal form…
Answer:
Okay what do you want to talk about ?
Step-by-step explanation:
Answer:
20'×15 in 54 inches
Step-by-step explanation:
The Best as a pool should be rectangular in shape and 54inches deep for safety of life's
<h3>
Answer:</h3>
(x, y) = (7, -5)
<h3>
Step-by-step explanation:</h3>
It generally works well to follow directions.
The matrix of coefficients is ...
![\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C-5%263%5Cend%7Barray%7D%5Cright%5D)
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
![\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B26%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-4%5C%5C5%262%5Cend%7Barray%7D%5Cright%5D)
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)