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Vika [28.1K]
3 years ago
12

Quentin and Micheal are on a bowling team. Below are their bowling scores.

Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer:

4

Step-by-step explanation:

Micheal's median:219

Quentin's median:215

219-215=4

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Scores from an exam are normally distributed with a mean of 85 and a standard deviation of 5. Suppose 188 students take the exam
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The mean is \mu=85 and standard deviation is \sigma=5. Then the variable X\sim N(85,5).

Use substitution Z=\dfrac{X-\mu}{\sigma}=\dfrac{X-85}{5}, then the variable Z\sim N(0,1).

The probability Pr(X>80) can be calculated in the following way:

for X=80, Z=\dfrac{80-85}{5} =-1 and Pr(X>80)=Pr(Z>-1). From the diagram Pr(Z>-1)=0.34+0.34+0.135+0.025=0.84.

Conclusion: if 188 students take the exam, then 188·0.84=157.92 (157) would receive a score above 80

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3 years ago
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A dresser contains six pairs of shorts one each in the colors, red, black, blue, green, khaki, and gray. The dresser also contai
marissa [1.9K]
Answer: 1/24

---------------------------------------------------------------------
---------------------------------------------------------------------

Work Shown:

A = selects green pair of shorts
B = selects gray t-shirt

P(A) = probability of selecting green shorts
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P(B) = probability of selecting gray t-shirt
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P(B) = 1/4

P(A and B) = probability of selecting green shorts AND gray t-shirt
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P(A and B) = (1/6)*(1/4)
P(A and B) = (1*1)/(6*4)
P(A and B) = 1/24

Note: The fraction 1/24 is approximately equal to 0.041667

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