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2 years ago

12

Evaluate the expression (3-2i)(3-2i) and write the result in the form a+bi ,where a is the real part of your answer and bis the

coefficient in front of the imaginary part

1 answer:

Maslowich2 years ago

4 0

Answer:

a = 5, b = -12

Step-by-step explanation:

By basic factoring, you get 9 - 12i + $4i^2$ . Since $i^2$ is simply -1, the expression evaluates to 9 - 12i - 4, which is 5 - 12i.

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Oksanka [162]

Answer:

○B. $\frac{\sqrt{6}}{2}$

Step-by-step explanation:

Trigonometric Identities

$\frac{y}{r} = sin\:θ$

$\frac{x}{r} = cos\:θ$

$\frac{y}{x} = tan\:θ$

$\frac{r}{x} = sec\:θ$

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<u>Radius Formula</u>

${y}^{2} + {x}^{2} = {r}^{2}$

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* Since we are talking about radii, we only want the NON-NEGATIVE root.

In this case, we will not be using the radius in our ratio, according to the trigonometric identity above because we are using the <em>tangent</em><em> </em>ratio:

$\frac{\sqrt{6}}{2} = \frac{-\sqrt{15}}{-\sqrt{10}} = \sqrt{1\frac{1}{2}}$

I am joyous to assist you anytime.

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