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dybincka [34]
3 years ago
8

Factor by gcf 6x2+3x+21 The 2 is supposed to be small.

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Given:

The expression is:

6x^2+3x+21

To find:

The factor of the given expression by GCF.

Solution:

We have,

6x^2+3x+21

Here, 3 is the greatest common factor (GCF) of 6x^2,3x,21.

Taking out GCF, we get

6x^2+3x+21=3(2x^2+x+7)

Therefore, the required factor form of the given expression is 3(2x^2+x+7).

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You plan to accumulate 100,000 at the end of 42 years by making the follow-
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Answer:

  Y = 479.17

Step-by-step explanation:

At the end of year 14, the balance from the deposits of X can be found using the annuity due formula:

  A = P(1+r/n)((1 +r/n)^(nt) -1)/(r/n)

where P is the periodic payment, n is the number of payments and compoundings per year, t is the number of years, and r is the annual interest rate.

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This accumulated amount continues to earn interest for the next 28 years, so will further be multiplied by 1.07^28. Then the final balance due to deposits of X will be ...

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__

The same annuity due formula can be used for the deposits of Y for the last 10 years of the interval:

  Ay = Y(1.07)(1.07^10 -1)/.07 = 14.783599Y

__

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From the latter, we have ...

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Y is 479.17

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3 years ago
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