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iVinArrow [24]
3 years ago
9

-1 3 2 0 d N e 4 f d = e = f= NE

Mathematics
1 answer:
andriy [413]3 years ago
8 0

Answer:

What is the question itself?

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The intercepts represent the points where the graph touches the axis the given. With that said, your y intercept is (0, -3) and the x intercept is (-1,0).
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Kelsey has $100 in an account. The intrest rate is %11 compounded annually. To the nearest cent, how much will she have in 2 yea
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~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$100\\ r=rate\to 11\%\to \frac{11}{100}\dotfill &0.11\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=100\left(1+\frac{0.11}{1}\right)^{1\cdot 2}\implies A=100(1.11)^2\implies A=123.21

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What is a axe on a graph?
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Step-by-step explanation:

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Two angles are complementary. If the measure of one angle is 20
mario62 [17]

Answer:

the smaller angle is 35 degrees.

Step-by-step explanation:

complementary angles are 90 degrees, so you would set your entire equation to 90.

we can use the variable x to represent the unknown smaller angle. we know that the larger angle is 20 more degrees than the unknown smaller angle (x). we can set up the equation like this:

x + x + 20 = 90

the first x represents the smaller angle and the x + 20 represents the other angle, which is 20 more than the smaller angle. we set it to 90 because we know that the entire angle will be 90 degrees

move variables and constants to opposite sides of the equal sign and combine like terms:

x + x = 90 - 20

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divide both sides by 2 to isolate 90:

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you can plug x back into the equation to check your answer if you want

hope this helps!! :)

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3 years ago
QUESTION #4 PLEASE HURRY
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A, I had to look for a second

Step-by-step explanation:

ACD and CEB are equal and CDE is not equal to either of them

so the right answer is A

4 0
3 years ago
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