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3 years ago

47° X Find the unknown angle measure

Mathematics

1 answer:

Mariana [72]3 years ago

6 0

Answer:

The angle measure is 43 degrees

Step-by-step explanation:

The right angle adds up to 90 degrees in whole, you already have 47 degrees so you want to subtract 47 from 90, then you will get your answer.

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Fantom [35]

Answer:

4.5 / B

Step-by-step explanation:

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3 years ago

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solve systems of equation. equation number 1: 9 x squared + 4 y squared equals 144. equation 2: x squared plus y squared equals

grigory [225]

$9x^{2} + 4y^{2} =144$
$x^{2} + y^{2}=24$

$9x^{2} + 4y^{2} =144$
$4x^{2} + 4y^{2}=96$
by the difference
5 $x^{2}$ =48
so x= $\sqrt{\frac{48}{5}}$ or x=- $\sqrt{\frac{48}{5}}$
and $y^{2}$ =24- $\frac{48}{5}$
then y= $\sqrt{\frac{72}{5}}$ or - $\sqrt{\frac{48}{5}}$

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3 years ago

A bag contains 5 black marbles, 9 white marbles, and 2 red marbles. One marble is to be chosen at random.

Andrej [43]

2/16
BC there are 2 red marbles out of 16 marbles in total

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3 years ago

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Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Stella [2.4K]

Given:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

Measure of major ∠AOB:

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

$Major \ \angle AOB=360-30$

$Major \ \angle AOB=330^{\circ}$

Thus, the measure of major angle is 330°

Length of the major arc ACB:

The length of the major arc ACB can be determined using the formula,

$m \widehat{ACB}=(\frac{\theta}{360})2 \pi r$

Substituting r = 3 and $\theta=330$ , we get;

$m \widehat{ACB}=(\frac{330}{360})2 \pi (3)$

$m \widehat{ACB}=\frac{1980}{360}\pi$

$m \widehat{ACB}=5.5 \pi$

Thus, the length of the major arc ACB is 5.5π m

8 0

3 years ago

I need step by step help with: 3x^1/3 + 2x^2/3 =5

Luba_88 [7]

If you write $y=x^{1/3}$ , you'll notice this is really just a quadratic equation that can be factorized:

$2x^{2/3}+3x^{1/3}-5=0\iff 2y^2+3y-5=0\iff (2y+5)(y-1)=0\iff(2x^{1/3}+5)(x^{1/3}-1)=0$

So you have

$2x^{1/3}+5=0\implies 2x^{1/3}=-5\implies x^{1/3}=-\dfrac52\implies x=-\dfrac{125}8$

and

$x^{1/3}-1=0\implies x^{1/3}=1\implies x=1$

5 0

3 years ago

47° X Find the unknown angle measure​

47° X Find the unknown angle measure