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VMariaS [17]
3 years ago
8

A Hindu might try to live a virtuous life to _____________.

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
The answer is B. Hindus believe in the concept of reincarnation, so obtaining good karma by living a virtuous life will help a person to be reborn of a higher caste (a higher position in the social order)  in their next life.
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Trent has some yellow, red, green, and blue cubes. Exactly 1/5 of the cubes are yellow and 1/6 of the cubes are green. Which of
Alika [10]

Answer:

Trent has at least 30 cubes.

Step-by-step explanation:

This is because the lowest common multiple of both 5 and 6 is 30. In order for you to get fractions with those denominators, there would have to be a total number in which they share the multiple.

8 0
3 years ago
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7/8 divided by 6 help me NOW please
slava [35]
I think is 0.14583 but I’m not sure
4 0
3 years ago
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Determine the central and radius of the circle of equation given below<br> x2+y2-4x+6y-12=0
Marianna [84]

Answer:

centre = (2, - 3 ) and radius = 5

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given

x² + y² - 4x + 6y - 12 = 0 ( add 12 to both sides )

x² + y² - 4x + 6y = 12 ( collect x/ y terms )

x² + 4x + y² + 6y = 12

using the method of completing the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(-2)x + 4 + y² + 2(3)y + 9 = 12 + 4 + 9

(x - 2)² + (y + 3)² = 25 ← in standard form

with (h, k ) = ( 2, - 3 ) and r = \sqrt{25} = 5

7 0
2 years ago
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The aorta is the largest artery in the human body. In the average adult, the aorta attains a maximum diameter of about 1.18 inch
Sholpan [36]
Well we know that 1 inch is 2.54 cm.  But how wide is .18?  Lets do .18 x 2.54 to get 0.4572.  Now lets add 2.54 + 0.4572 to get 2.9972.  This means that the maximum width of the aorta is 2.9972 cm.  Hope this helped :)
3 0
3 years ago
F(x) = 3x<br> g(x) = x2 – 5x - 9<br> Find (fºg)(x).
Eddi Din [679]

Answer:

\boxed{(f.g)(x) = 3 {x}^{3}  - 15 {x}^{2}  - 27x}

Given:

f(x) =  x + 2 \\  \\ g(x) =  3x + 5

To Find:

(f.g)(x) = f(x) \times g(x)

Step-by-step explanation:

=  > f(x) \times g(x) = (3x)( {x}^{2}  - 5x - 9) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = (3x \times  {x}^{2} ) - (3x \times 5x) - (3x \times 9)\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 3 {x}^{3}  - 15 {x}^{2}  - 27x

8 0
3 years ago
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