To find the zeros set the equation equal to zero:
x^2 - 5x +4 = 0
Factor:
(x-4) (x-1) = 0
Now solve each set of parenthesis so that they equal zero:
(x-4) = 0, x =4
(x-1) = 0, x = 1
The zeros are 1,4
Answer:
x=9
y=12
Step-by-step explanation:
you know what the value of x is in terms of the second equation
so put that value into the first equation
so
-5(2y-15) + 4y = 3
-10y + 75 + 4y = 3
-6y + 75 = 3
-6y = -72
y = 12 (now we have the actual value of y, just substitute this into any of the first two original functions)
x = 2(12) - 15
x = 24 - 15
x = 9
In this question, the condition asked is two which was
1. The dice sum >7 (notice that >7 mean at least 8)
2. One of the two dice show a 2
It will be easier to fulfill the No.2 condition first so you can divide the probability into two,
Case 1: 1st dice show 2: then the second dice need to be 6 to made it sum>7
Case 2:2nd dice show 2: then the second dice need to be 6 to made it sum>7
The probability for a dice showing 2 is 1/6. The probability for a dice showing 6 is 1/6. Then the probability is 1/6 * 1/6= 1/36 for each case
Since case 1 and case 2 has same probability, then you just need to multiply 1/36 *2 = 1/18
Answer:
Since we have g(4) just replace every x with 4:
g(4) = (4² -6)/(3×4 + 10)
= (16 - 6)/(12 + 10)
= 10/22 = 5/11
