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GREYUIT [131]
2 years ago
5

Find the length of a third side of a triangle given two sides. please

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0

Answer:  # 4.) 9.4

#5.) 10.2 cm  

#6.) 5 inches .

Step-by-step explanation: Assuming that a right triangle is expected, use the <u><em>Pythagorean Theorem</em></u> to calculate the third side: a² + b² = c²

5^{2}+8^{2}=89  Then take the square root of 89. A calculator is handy for most of these!

√89 = 9.433981 .  Round to 9.4

2^{2}+10^{2}=104

√104 = 10.1980  Round to 10.2 <u>Remember to include the units, cm in the answer.</u>

<u>Memorize this one:</u>

<u>Given side lengths of 3 & 4, the hypotenuse is 5!</u>

3² + 4² = 5²   Called a "Pythagorean Triple"

9 + 16 = 25

The square on the hypotenuse is a perfect square of 5

No calculator necessary, and you are likely to see this ratio in other questions.

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11.45

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a painter bought 8 gallons of paint just enough to cover 2 rooms. One room is twice the size of the other and requires only 2 co
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So, he's got 8 gallons of paint, to paint the two rooms, of the two rooms, one is twice as big as the other

now, "x" is how many gallons to paint the larger room with only one coat, however, the larger room uses 2 coats, so, the larger room uses 2x of paint
now, the client declined to paint the smaller one

so hmmm as I read... well, we dunno how many coats will go to the smaller room for one, we know the larger will use 2 coats, or 2x.. if we assume the smaller room was going to use say 1 coat or 1/2x

then one can say the painter bought enough for both rooms, 1coat for the small one and 2coats for the larger one

so, the paint the larger room, you'll 2x of paint, for 2coatsand to paint the smaller room, you'll need 1/2 x, because x gallons is how much is needed for the larger room, but the larger room is twice as big, thus the smaller room uses 1/2 of that in gallons

thus, with those assumptions, that the small room will use only 1 coat
\bf \cfrac{1}{2}x+2x=8\implies \cfrac{5x}{2}=8\implies x=\cfrac{16}{5}
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now, the client decides to skip the smaller roomso, the painter will only need 2x gallons then

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3 years ago
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how far would a 4.0 cm tall object be located from a reflecting surface with a focal lenght that is equal to 5 cm if it is to cr
katrin [286]

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

Use the mirror equation:

1/di + 1/do = 1/f

where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)

Substitute and solve for do.

1/do + 1/(-10 cm) = 1/(15 cm)

1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)

do = 6 cm

Hope it helps you

Regards,

Rachana

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Divide both sides by -12.

(Because we're dividing by a negative, the inequality sign flips.)

<h3><u>4- < x</u></h3>
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