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madam [21]
3 years ago
5

Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.

Mathematics
1 answer:
Ann [662]3 years ago
6 0

Given:

Consider the given function is:

f(x)=x^2-8x+13

To find:

The average rate of change of the function over the interval -1\leq x\leq 6.

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}

We have,

f(x)=x^2-8x+13

At x=-1,

f(-1)=(-1)^2-8(-1)+13

f(-1)=1+8+13

f(-1)=22

At x=6,

f(6)=(6)^2-8(6)+13

f(6)=36-48+13

f(6)=1

Now, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is:

m=\dfrac{f(6)-f(-1)}{6-(-1)}

m=\dfrac{1-22}{7}

m=\dfrac{-21}{7}

m=-3

Therefore, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is -3.

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Answer:

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