Answer:
ever find the answer? I cant manage to find it
Answer:

Step-by-step explanation:
![if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) = {4}^{2} \\ f[g(4)] = 4( {4}^{2} ) + 2 \\ f[g(4)] = 4(16) + 2 \\ f[g(4)] =64 + 2 \\ f[g(4)] = \boxed{66}](https://tex.z-dn.net/?f=%20if%20%5C%3A%20the%20%5C%3A%20question%20%5C%3A%20is%20%5C%3A%20f%5Bg%284%29%5D%20%5C%5C%20then%20%5C%3A%20at%20%5C%3A%20first%20%5C%3A%20solve%20%5C%3A%20for%20%5C%3A%20g%284%29%20%5C%5C%20g%284%29%20%3D%20%20%7B4%7D%5E%7B2%7D%20%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%28%20%7B4%7D%5E%7B2%7D%20%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%2816%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D64%20%2B%202%20%5C%5C%20%20%20f%5Bg%284%29%5D%20%20%3D%20%20%5Cboxed%7B66%7D)
You need to include an image so I can help
Answer:
c
Step-by-step explanation:
Here's how this works:
Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:
![[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?](https://tex.z-dn.net/?f=%5Bsin%28x%29cos%28x%29%5D%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%2B%5Bsin%28x%29cos%28x%29%5D%5Cfrac%7Bcos%28x%29%7D%7Bsin%28x%29%7D%20%3D%3F)
In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

Put everything over the common denominator now:

Since
, we will make that substitution:

We could separate that fraction into 2:
×
and 
Therefore, the simplification is
sec(x)csc(x)