He will not need to pay a shipping fee because 12*9.75 is more than $100.
Step-by-step explanation:
m is for slope of the line that passes through



Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
Step-by-step explanation:
In the given equation, the "like terms" are the constants 5/8 and 44.
It simplifies the math if we eliminate the fractions first. Note that 0.75 = 6/8, so now we have:
8(6/8)s - 8(5/8) = 44).
Multiplying all three terms by 8 (above) yields
8(6s) - 8(5) = 8(44), or
48s = 8(44 + 5), or 48s = 8(49)
Dividing both sides by 48 yields s: s = 8(49/48)
Review "like terms:" These are terms that have at least one characteristic in common. 5/8 and 44 are like terms because they are only constants (no variables are present). We must add 5/8 and 44. 0.75s does not have a "like term" in the given equation.