Answer:
who's he, is it me, cuz id call that a failed abortion
The inequality that can be used to determine the number of boxes of donuts, d, they must sell in order to meet their goal is $1500 ≥ $575 + $5d.
<h3>What is the inequality?</h3>
Here are inequality signs and what they denote:
- > means greater than
- < means less than
- ≥ means greater than or equal to
- ≤ less than or equal to
Total amount that needs to be raised ≥ amount made at the fruit sale + (profit per box x number of boxes)
$1500 ≥ $575 + $5d
To learn more about inequality, please check: brainly.com/question/5031619
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<span>Percent error is the percentage ratio of the observed value and the true value difference over the true value so you don't need plus or minus signs. Thanks!</span>
Answer:
Step-by-step explanation:
1) Use Division Distributive Property: (x/y)^a = x^a/y^a.
2) Multiply both sides by 27^x - 8.
3) Use the product rule: x^a x^b = x^a+b.
4) Simplify 1 + x - 8 to x - 7.
5) Use Definition of Common Logarithm: b^a = x if and only if log<u>b</u><u> </u>(x) = a.
6) Use Change of Base Rule.
7) Use rule of 1: log 1 = 0.
8) Simplify 0/log_27 to 0.
9) Add 7 to both sides.
10) Switch sides.
<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>7</u><u>.</u>
Answer:
0.903264
Step-by-step explanation:
Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.
Let A' = the event that A fails, B' = B fails and C'= C fails.
Probability that no circuit board fails = Prob (A'B'C')
= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent
= (1-0.03)(1-0.04)(1-0.03)
= 0.903264
