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3 years ago

Need this quickkkkkk

Mathematics

2 answers:

Alexus [3.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

cestrela7 [59]3 years ago

4 0

Answer:

It’s b

Step-by-step explanation:

You might be interested in

Mrs.Helio has 2 3/4 acres of farmland. she will plant corn on 1/4 of this land, potatoes on 1/12 of the land, wheat on 5/8 of th

Minchanka [31]

2 3/4 acres is the same as 11/4 acres
To find how much of the land is beans, find how much is already taken up, and the rest is beans.
Farmland-Corn-Potatoes-Wheat=Beans
1-(1/4)-(1/12)-(5/8)=1/24

Corn: (1/4)x(11/4)=11/16 acres
Potatoes: (1/12)x(11/4)=11/48 acres
Wheat: (5/8)x(11/4)=55/32 acres or 1 23/32 acres
<span>Beans: (1/24)x(11/4)=11/96 acres

Hope this helps!</span>

4 0

3 years ago

A large cable company reports the following:

Step2247 [10]

Answer:

$P(Cable\ TV\ only) = 50\%$

$P(Internet\ |\ cable\ TV) = 31.25\%$

$P(exactly\ 2\ services) = 23\%$

$P(Internet\ and\ cable\ TV \only) = 23\%$

Step-by-step explanation:

Given

$Cable\ TV = 80\%$

$Internet = 44\%$

$Telephone = 29\%$

$Cable\ TV\ and\ Internet = 25\%$

$Cable\ TV\ and\ Telephone = 20\%$

$Internet\ and\ Telephone = 23\%$

$All\ Services = 15\%$

Solving (a): A) P(cable TV only).

First, we calculate n(cable TV only)

This is calculated as:

$n(cable\ TV\ only) = (Cable\ TV) - (Cable\ TV\ and\ Internet) - (Cable\ TV\ and\ Telephone) + (All\ Services)$

$n(cable\ TV\ only) = 80\% - 25\% - 20\% + 15\%$

$n(cable\ TV\ only) = 50\%$

The probability is:

$P(Cable\ TV\ only) = \frac{n(Cable\ TV\ only)}{100\%}$

$P(Cable\ TV\ only) = \frac{50\%}{100\%}$

$P(Cable\ TV\ only) = 50\%$

Solving (b): P(Internet | cable TV).

This is calculated as:

$P(Internet\ |\ cable\ TV) = \frac{Cable\ TV\ and\ Internet}{Cable\ TV}$

$P(Internet\ |\ cable\ TV) = \frac{25\%}{80\%}$

$P(Internet\ |\ cable\ TV) = \frac{25}{80}$

$P(Internet\ |\ cable\ TV) = 31.25\%$

Solving (c): P(exactly 2 services).

This is calculated as:

$P(exactly\ 2\ services) = (Cable\ TV\ and\ Internet - All) + (Cable\ TV\ and\ Telephone - All) + (Internet\ and\ Telephone - All)$

$P(exactly\ 2\ services) = (25\% - 15\%) + (20\% - 15\%) + (23\%-15\%)$

$P(exactly\ 2\ services) = (10\%) + (5\%) + (8\%)$

$P(exactly\ 2\ services) = 23\%$

Solving (d): P(Internet and cable TV only).

This is calculated as:

$P(Internet\ and\ cable\ TV \only) = \frac{(Internet\ and\ cable\ TV \only)}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{1}$

$P(Internet\ and\ cable\ TV \only) = 23\%$

4 0

3 years ago

Make m the subject of the following equation:<br> x = 4k(n + m)

inna [77]

Step-by-step explanation:

x=4kn+4km

x-4kn=4km

divide both sides by 4k

m=x-n

8 0

3 years ago

Angles PTQ and STR are vertical angles and congruent.

iren [92.7K]

9514 1404 393

Answer:

(a) QP and SR

Step-by-step explanation:

The congruent central angles intercept congruent arcs QP and SR. Chords of congruent arcs are congruent.

chords QP and SR are congruent

4 0

3 years ago

The following data represent the discrete probability distribution for the number of stars that reviewers have a first edition s

Shkiper50 [21]

Answer:

Step-by-step explanation:

given that the following data represent the discrete probability distribution for the number of stars that reviewers have a first edition statistics reference book.

Stars 5 4 3 2 1

Probability 25% 35% 20% 10% 10%

H0: Second edition is as per the above probabilities

Ha: atleast one is different from the above probability

(two tailed chi square test)

Alpha = 0.025

Assuming H0 to be true we calculate expected frequencies for total 80

chi square calculatons are shown below

df = 4

5 4 3 2 1 Total

Observed 28 28 13 6 5 80

Expected 20 28 16 8 8 80

chi square

(O_E)^2/E 3.2 0 0.5625 0.5 1.125 5.3875

p value =0.1455

Since p value >0.025, we accept H0

The expected requency of three-star reviews is ________.16

3 0

4 years ago