Question

Find the midpoint of AB for: A(7,0)|and B(0,3)​

Answer 1

Answer:

$\boxed {\boxed {\sf (\frac {7}{2}, \frac{3}{2}) \ or \ (3,5, 1.5) }}$

Step-by-step explanation:

The midpoint is essentially a point with the average of the 2 x-coordinates and the 2 y-coordinates.

The formula is:

$(\frac {x_1+x_2}{2}, \frac{y_1+y_2}{2})$

We are given two points: A (7,0) and B (0, 3). Remember points are written as (x, y).

Therefore,

$x_1= 7 \\y_1=0 \\x_2=0 \\x_2=3$

Substitute the values into the formula.

$(\frac {7+0}{2}, \frac{0+3}{2})$

Solve the numerators first.

$(\frac {7}{2}, \frac{3}{2})$

The midpoint can be left like this because the fractions are reduced, but it can be written as decimals too.

$(3.5, 1.5)$