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Ede4ka [16]
3 years ago
15

Jamie has 3 game tickets more than twice her brother's

Mathematics
1 answer:
shtirl [24]3 years ago
3 0
You mean Jamie has two game tickets more than 3 times her brother
40 | 122
50 | 152
60 | 182

Graph the coordinates
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How do you get over a boy who has left you 6 times..?
PolarNik [594]

Who has left me for 6 times man

seriously

I wouldn't get into that boy firstly

<em>Lol</em>

4 0
2 years ago
Please answer the question i will give brainliest <br><br> A. 1/3<br> B. - 1/3<br> C. -3<br> D.3
daser333 [38]

Step-by-step explanation:

the answer would be a. 1/3

6 0
2 years ago
Read 2 more answers
(x – 2) = –14(x – 8)
muminat

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x = 38/5

Decimal Form:

x = 7.6

Mixed Number Form:

x = 7/3/5

7 0
2 years ago
Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....
nadezda [96]

Answer:

Tn = 4(-6)^n-1

Step-by-step explanation:

Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....

The sequence is a geometric sequence

Tn = ar^n-1

a is the first term

a = 4

r = -24/4 =144/-24

r = -6

Substitute

Tn = 4(-6)^n-1

3 0
2 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
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