B. lx+4l +2
hope it helps
1. i’m not sure what you have worked with.
2. area is how much space is within a 2D shape.
3. Volume is the amount of mass that a 3D shape takes up.
4. You find the combined area of a 3D shape by finding the individual area of each shapes on the outside of the 3D shape and then add them up.
5. i’m not sure what you mean by “give an example of why that would be a good measurement to know”
Answer: 3
x
−
2
y
−
15
=
0
Explanation:
We know that,
the slope of the line
a
x
+
b
y
+
c
=
0
is
m
=
−
a
b
∴
The slope of the line
2
x
+
3
y
=
9
is
m
1
=
−
2
3
∴
The slope of the line perpendicular to
2
x
+
3
y
=
9
is
m
2
=
−
1
m
1
=
−
1
−
2
3
=
3
2
.
Hence,the equn.of line passing through
(
3
,
−
3
)
and
m
2
=
3
2
is
y
−
(
−
3
)
=
3
2
(
x
−
3
)
y
+
3
=
3
2
(
x
−
3
)
⇒
2
y
+
6
=
3
x
−
9
⇒
3
x
−
2
y
−
15
=
0
Note:
The equn.of line passing through
A
(
x
1
,
y
1
)
and
with slope
m
is
y
−
y
1
=
m
(
x
−
x
1
)3
x
−
2
y
−
15
=
0
Explanation:
We know that,
the slope of the line
a
x
+
b
y
+
c
=
0
is
m
=
−
a
b
∴
The slope of the line
2
x
+
3
y
=
9
is
m
1
=
−
2
3
∴
The slope of the line perpendicular to
2
x
+
3
y
=
9
is
m
2
=
−
1
m
1
=
−
1
−
2
3
=
3
2
.
Hence,the equn.of line passing through
(
3
,
−
3
)
and
m
2
=
3
2
is
y
−
(
−
3
)
=
3
2
(
x
−
3
)
y
+
3
=
3
2
(
x
−
3
)
⇒
2
y
+
6
=
3
x
−
9
⇒
3
x
−
2
y
−
15
=
0
Note:
The equn.of line passing through
A
(
x
1
,
y
1
)
and
with slope
m
is
y
−
y
1
=
m
(
x
−
Explanation:
the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
rearrange
2
x
+
3
y
=
9
into this form
⇒
3
y
=
−
2
x
+
9
⇒
y
=
−
2
3
x
+
3
←
in slope-intercept form
with slope m
=
−
2
3
Given a line with slope then the slope of a line
perpendicular to it is
∙
x
m
perpendicular
=
−
1
m
⇒
m
perpendicular
=
−
1
−
2
3
=
3
2
⇒
y
=
3
2
x
+
b
←
is the partial equation
to find b substitute
(
3
,
−
3
)
into the partial equation
−
3
=
9
2
+
b
⇒
b
=
−
6
2
−
9
2
=
−
15
2
⇒
y
=
3
2
x
−
15
2
←
equation of perpendicular lineExplanation:
the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
rearrange
2
x
+
3
y
=
9
into this form
⇒
3
y
=
−
2
x
+
9
⇒
y
=
−
2
3
x
+
3
←
in slope-intercept form
with slope m
=
−
2
3
Given a line with slope then the slope of a line
perpendicular to it is
∙
x
m
perpendicular
=
−
1
m
⇒
m
perpendicular
=
−
1
−
2
3
=
3
2
⇒
y
=
3
2
x
+
b
←
is the partial equation
to find b substitute
(
3
,
−
3
)
into the partial equation
−
3
=
9
2
+
b
⇒
b
=
−
6
2
−
9
2
=
−
15
2
⇒
y
=
3
2
x
−
15
2
←
equation of perpendicular line
When (-5, 2) is reflected across the y-axis then it becomes (5, 2). When (-5, 2) is reflected across the x-axis, it becomes (-5, -2)
I hope this helps out!
