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LenaWriter [7]
2 years ago
8

Solve for x. It’s in the picture

Mathematics
1 answer:
kaheart [24]2 years ago
5 0

Answer:

c,x=12

Step-by-step explanation:

5/6x+4=x+2

2=1/6x

x=12

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Please Answer, No links! reporting right away!.. giving brainliest and more points!
loris [4]

Answer:

A) 154x89 _s2

s

Step-by-step explanation:

A) 154x89 _s2

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4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20x-12%3D14" id="TexFormula1" title="\sf x-12=14" alt="\sf x-12=14" align="absmiddle" cl
suter [353]
Answer:

X - 12 = 14
+12. +12

X = 26
7 0
2 years ago
Read 2 more answers
Perform the indicated operation. Show all necessary work. a -2-(-9) b -2 -9 c -2- (-9)-(-2
aksik [14]

Answer:

a=7 b=11 c=9

Step-by-step explanation:

-2-(9)      -2-(9) = -2+9=7 b -2-9=-11 c -2-(-9)-(-2) = -2+9+2=9

7 0
3 years ago
Read 2 more answers
How do you solve these?
Murrr4er [49]

Answer:

Step-by-step explanation:

The first and only rule really is to factor these down to their primes and then apply a very simple rule

For every prime, take out 1 prime for every prime under the root sign that equals the index. The rest are thrown away.

That's very wordy. Let's try and see what it means with an example

Take sqrt(27) The index is 1/2 (square root) That means we need two threes in order to apply the rule.

sqrt(27) = sqrt(3 * 3 * 3 ) For every two primes take out 1 and throw one away.

sqrt(27) = 3 sqrt(3) You can't take out that 3rd 3.

64 = 2 * 2 *2 *2 *2 * 2

4th root 64 =  <u>2*2*2 </u><u>*2</u><u> </u>* 2 *2

for every 4th root, you get to take 1 out and throw three away.

4th root 64 = 2 fourth root (2*2)

4th root 64 = 2 fourth root (4)

- 189 = -  <u>3 * 3 * </u><u>3</u> * 7

cuberoot (- 189) = For every 3 roots, you get to pull 1 out and throw the other two away.

3 cube (- 7) is your answer.

72 = 2 * 2 * 2 * 3 * 3

cube root (72) = 2 cube root(9) You don't have enough threes to do any more than what is done.

6 0
2 years ago
A woodworking company handcrafts two types of birdhouses. One is large and the other is small. Both types of houses go through t
Softa [21]

Answer:

44 large houses and 16 small housed should be sold per month to obtain the best returns

Step-by-step explanation:

Let x denotes large bird houses and y denotes small bird houses.

We are given that  Both types of houses go through two technicians; first a shaper and then a painter

The large house requires two hours of the shaper's time and and then a painter.

The small house requires one hour of the shaper's time and two hours of the painter's time.

We are given that The shaper has 104 hours and the painter has 76 hours of time available this month.

So, 2x+ y \leq 104

x+2y \leq76

x \geq 0

y \geq 0

Plot the lines on the graph

Refer the attached graph

The boundary points of feasible region are :

(0,0),(0,38),(44,16),(52,0)

Profit on the large house is $6 and on the small house is $11.

So, P=6x+11y

At(0,0)

P=0

At(0,38)

P=6(0)+11(38)=418

At (44,16)

P=6(44)+11(16)=440

At(52,0)

P=6(52)+11(0)=312

So, The company gets the best returns at(44,16)

So, 44 large houses and 16 small housed should be sold per month to obtain the best returns

5 0
3 years ago
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