Answer:
B. 1730 PST
Explanation:
First it is important to know that the flight lasted for 2 hours and 15 minutes, hence the first thing to do in this case is to add the duration of flight to the time of departure.
Time of departure = 1615 MST
Flight duration = 2:15
Hence we get 18:30 MST
Then we convert MST to PST by subtracting 1
1830 -1.00 = 1730 PST
Explanation:
Other events at that time are canceled, and the meeting cannot be canceled by the organizer.
The agenda is updated with the user’s contact information, and other events at that time are canceled.
The meeting cannot be canceled by the organizer, and the agenda is updated with the user’s contact information.
The meeting organizer is notified, and a copy of the meeting is added to the user’s Outlook calendar.
Answer:
sqrt(area)
Explanation:
- Here sqrt is a short form of square root.
- area is a variable name having he area of square.
- When the function is called, it will give the square root of the value stored in variable area.
As we have to find the length of the diagonal, we must knew that as all sides of the square are same in length so are the diagonals. This means that each of the four sides of the square and it diagonals are equal in length.
So a square has: length=breadth=diagonal
As Area= length*breadth
√area = length (as length = diagonal length)
So √area = diagonal length
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
