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ANTONII [103]
3 years ago
11

I don't understand this question, help me, someone, please

Mathematics
1 answer:
vodomira [7]3 years ago
3 0

Answer:

Arranging the terms from least to greatest:

\frac{3039}{1000}

Now actual terms arranged from least to greatest will be:

3\frac{39}{1000}

Step-by-step explanation:

We need to arrange the weights 3\frac{1}{5} ,3\frac{39}{1000},3\frac{99}{100},3\frac{52}{10} from least to greatest.

To arrange them in least to greatest we need to convert them into improper fractions and then make their denominators same.

3\frac{1}{5}=\frac{16}{5} \\3\frac{39}{1000}=\frac{3039}{1000} \\3\frac{99}{100}=\frac{399}{100} \\3\frac{52}{10}=\frac{82}{10}

Now, Making their denominator same by taking LCM of 5,1000,100 and 10

The LCM is 1000

Now the fractions will become:

\frac{16}{5}=\frac{16*200}{5*200}=\frac{3200}{1000}

\frac{399}{100}=\frac{399*10}{100*10}=\frac{3990}{1000}

\frac{82}{10}=\frac{82*100}{10*100}=\frac{8200}{1000}

Now we have fractions: \frac{3200}{1000},\frac{3990}{1000},\frac{8200}{1000},\frac{3039}{1000}

Now the smallest term will be one having smallest numerator

Arranging the terms from least to greatest:

\frac{3039}{1000}

Now actual terms arranged from least to greatest will be:

3\frac{39}{1000}

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s2008m [1.1K]

Answer:

D) <1 and <2, <1 and <8, <2 and <3, <3 and <8

Step-by-step explanation:

Supplementary angles are angles that add to 180 degrees. So, D is correct.

5 0
3 years ago
Let X equal the number of typos on a printed page with a mean of 4 typos per page.
timama [110]

Answer:

a) There is a 98.17% probability that a randomly selected page has at least one typo on it.

b) There is a 9.16% probability that a randomly selected page has at most one typo on it.

Step-by-step explanation:

Since we only have the mean, we can solve this problem by a Poisson distribution.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

In this problem, we have that \mu = 4

(a) What is the probability that a randomly selected page has at least one typo on it?

Thats is P(X \geq 1). Either a number is greater or equal than 1, or it is lesser. The sum of the probabilities must be decimal 1. So:

P(X < 1) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X < 1)

In which

P(X < 1) = P(X = 0).

So

P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183

P(X \geq 1) = 1 - P(X < 1) = 1 - 0.0183 = 0.9817

There is a 98.17% probability that a randomly selected page has at least one typo on it.

(b) What is the probability that a randomly selected page has at most one typo on it?

This is P = P(X = 0) + P(X = 1). So:

P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183

P(X = 1) = \frac{e^{-4}*4^{1}}{(1)!} = 0.0733

P = P(X = 0) + P(X = 1) = 0.0183 + 0.0733 = 0.0916

There is a 9.16% probability that a randomly selected page has at most one typo on it.

3 0
3 years ago
Please help hurry. Drag each number to the correct location on the table.
Kaylis [27]

Answer:

Between -2 and 1 is -0.5 and 0.5

Below -2 is -4.5 and -2.5

Above 1 is 4 and 1.5

Step-by-step explanation:

Can i have brainliest?

8 0
3 years ago
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Answer:

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6 0
3 years ago
A satellite orbits the Earth at a height of 343 kilometers. If the satellite makes 8 revolutions around the Earth, how many kilo
Olegator [25]

The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.

<h3>What is the distance in kilometres covered by the satellite after 8 revolutions?</h3>

Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;

D = 6371 + (343)×2

Hence, we have; diameter, D = 7057 km.

Hence, the distance travelled after 8 revolutions is;

C = 8 × πd

C = 8 × 3.14 × 7057

C = 177,271.8 km.

Read more on circumference of a circle;

brainly.com/question/20489969

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4 0
1 year ago
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