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3 years ago

Help in class ez rly ez

Mathematics

2 answers:

KiRa [710]3 years ago

8 0

Answer:

The slope is 4x

The y-intercept is -5

Slope-intercept form = y = 4x - 5

Step-by-step explanation:

I hope this helps.

oee [108]3 years ago

5 0

Answer:

mark lazyboss330 as brainliest :D

why havent u been active for like a month? :c

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what is the equation of a line that passes through the points (0,5) and (4,8)? write the answer in slope-intercept form.

Sergio039 [100]

Answer:

Step-by-step explanation:

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (4, 8) and (0, 5) → b = 5.

Calculate the slope:

$m=\dfrac{5-8}{0-4}=\dfrac{-3}{-4}=\dfrac{3}{4}$

Therefore we have the equation of the line:

$y=\dfrac{3}{4}x+5$

4 0

3 years ago

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The volume of a where is 38808 cm cube .find the radius

Leokris [45]

638272 is the radius I think

4 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Valentin [98]

Remark

At first glance, one would think this problem isn't possible. But if you use the magnifying glass, you see that it is.

Solve

25 carrots puts you somewhere to the left of the shaded area, so C and D are both wrong.

That leaves you with A or B. You need 30 carrots (or just very slightly less) at least to solve this problem. The way to distinguish between A and B is to look at the line that goes from lower right to upper left. When you magnify this graph, you see that at 30 carrots the line or boundary goes through 20 cucumbers. 21 is just very slightly above that and 25 is far above the other line. 21 cucumbers is the only possible right answer for the number of cucumbers. 25 is too high. B is wrong. The answer is A.

4 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

I need the length of c in the triangle shown. plz i need help badly.

lesya [120]

Answer:

c=10

Step-by-step explanation:

6^2+8^2=c^2

36+64=c^2

100=c^2

10=c

8 0

3 years ago