(2 x 103 x 3 x 105) = 64890
2 x 10 -2 = 20 - 2 = 18
64890 / 18
3605
Or (206 x 315) / 20 - 2
2 13/25+3 and 99 one hundreds
Answer:
6v^3
Step-by-step explanation:
i think so. dont critisize me
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be: