Answer:
B.
Step-by-step explanation:
The ratio of Claire's songs to her mother's songs = 3 : 2
A.
3 : 2 = 3/2
9 : 6 = 9/6 = 3/2
12 : 10 = 12/10 = 6/5
B.
3 : 2 = 3/2
6 : 4 = 6/4 = 3/2
15 : 10 = 15/10 = 3/2
C.
3 : 2 = 3/2
4 : 3 = 4/3
5 : 4 = 5/4
D.
3 : 2 = 3/2
4 : 6 = 4/6 = 2/3
20 : 30 = 20/30 = 2/3
The table which shows the correct ratio and two equivalent ratios is B
Answer:
C. Alternate Exterior Angles Theorem
Step-by-step explanation:
I took the test
Volume of a volleyball (a sphere) = 4/3πr³
= 4/3π(11.4)³
= 1975.392π
= 6210 cm³ (to 3 significant figures)
The volume of a volleyball with a radius of 11.4 cm will be 6210 cm³.
Answer:
487=3x-17
487+17=3x-17+17
3x=53
3x/3=53/3
x=168
Step-by-step explanation:
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
