Answer:
(2, 1 )
Step-by-step explanation:
Given the 2 equations
y = 6x - 11 → (1)
- 2x - 3y = - 7 → (2)
Substitute y = 6x - 11 into (2)
- 2x - 3(6x - 11) = - 7 ← distribute and simplify left side
- 2x - 18x + 33 = - 7
- 20x + 33 = - 7 ( subtract 33 from both sides )
- 20x = - 40 ( divide both sides by - 20 )
x = 2
Substitute x = 2 into (1) for corresponding value of y
y = 6(2) - 11 = 12 - 11 = 1
Solution is (2, 1 )
Answer:
The ordered pairs for 1 and 3 are:
(1,2) (3,8)
Now use the slope formula:
(y2-y1)/(x2-x1)
(8-2)/(3-1)= 6/2 = 3
Step-by-step explanation:
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
First, we subtract 12x from both sides. We then get -4y=-12x+48. We then divide this by -4 on both sides to get the y by itself. We then get that the equation is y=3x-12.
