Answer:
The simplified form of the given expression is 
Step-by-step explanation:
Here, the given expression is:
Now to simplify the given expression, perform operations on LIKE TERMS:
We get:
![-3 + (\frac{2}{3}) y - 4 - (\frac{1}{3})y =( -3 - 4) + [(\frac{2}{3}) y- (\frac{1}{3})y]\\= - 7 + [(\frac{2}{3}) -(\frac{1}{3})]y = -7 + [\frac{2-1}{3}]y\\ = -7 + (\frac{1}{3})y\\ \implies -3 + (\frac{2}{3}) y - 4 - (\frac{1}{3})y = -7 + (\frac{1}{3})y](https://tex.z-dn.net/?f=-3%20%2B%20%28%5Cfrac%7B2%7D%7B3%7D%29%20y%20-%204%20-%20%28%5Cfrac%7B1%7D%7B3%7D%29y%20%20%3D%28%20-3%20%20-%204%29%20%20%2B%20%5B%28%5Cfrac%7B2%7D%7B3%7D%29%20y-%20%28%5Cfrac%7B1%7D%7B3%7D%29y%5D%5C%5C%3D%20-%207%20%20%2B%20%5B%28%5Cfrac%7B2%7D%7B3%7D%29%20-%28%5Cfrac%7B1%7D%7B3%7D%29%5Dy%20%20%3D%20-7%20%2B%20%5B%5Cfrac%7B2-1%7D%7B3%7D%5Dy%5C%5C%20%3D%20-7%20%2B%20%28%5Cfrac%7B1%7D%7B3%7D%29y%5C%5C%20%5Cimplies%20-3%20%2B%20%28%5Cfrac%7B2%7D%7B3%7D%29%20y%20-%204%20-%20%28%5Cfrac%7B1%7D%7B3%7D%29y%20%3D%20%20%20-7%20%2B%20%28%5Cfrac%7B1%7D%7B3%7D%29y)
Hence the simplified form of the given expression is
Answer:
your answer would be X>-4
<h3>
Answers:</h3>
- ST = 23
- RU = 8
- SV = 5
- SU = 10
====================================================
Explanation:
Focus on triangles SVT and UVT.
They are congruent triangles due to the fact that SV = VU and VT = VT. From there we can use the LL (leg leg) theorem for right triangles to prove them congruent.
Since the triangles are the same, just mirrored, this means ST = UT = 23.
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Following similar reasoning as the previous section, we can prove triangle RVU = triangle RVS.
Therefore, RS = RU = 8
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SV = VU = 5 because RT bisects SU.
Bisect means to cut in half. The two smaller pieces are equal.
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SU = SV + VU = 5+5 = 10
Refer to the segment addition postulate.
Answer:
Step-by-step explanation:
Let the weight of the bag of sand with an unknown weight be given as "x" pounds. Then, the difference between the weight of an average bag of sand which is given to be as 22.3 pounds, is given as 
. Therefore, the absolute value function describing the difference between the weight of an average bag of sand and a bag of sand with an unknown weight will be given as: 
.
Let us represent this by f(x) or y. And thus, we get:
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
