The position function of a particle is given by:
The velocity function is the derivative of the position:
The particle will be at rest when the velocity is 0, thus we solve the equation:
The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
![t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting:
![\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81-4%282%29%28-18%29%7D%7D%7B2%282%29%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81%2B144%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B225%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm15%7D%7B4%7D%20%5Cend%7Bgathered%7D)
We have two possible answers:
We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
Answer:
$25
Step-by-step explanation:
We know,
Monthly interest = (Principal × Interest rate) ÷ 12
Given,
Loan principal = $3,000
Interest rate = 10% = 0.10
Therefore, monthly interest = ($3,000 × 0.10) ÷ 12
Monthly interest = $300 ÷ 12
Monthly interest = $25
Therefore, the principal amount to be paid per month is = $(96.80 - 25) = $71.80.
So, Jamison will pay $25 as interest for the 36-month $3,000 loan.
Answer:
0.000000014
Step-by-step explanation:
1.4 × 
= 
= 0.000000014
Answer:
Step-by-step explanation:
Given
Rotation = +270 degrees
Required
Determine the new coordinates of Q (i.e. Q')
When a point (x,y) is rotated +270° about the origin, the new coordinates is: (y,−x)
So:
Where:
and 
Q' will be:
Answer:
(5/2,5)
Step-by-step explanation:
