Answer:
From the photo above i interpreted the question and drew a triangle to make it easier to solve
Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)
Tan θ =Opp/Adj
Tan 22°=15/a
Cross Multiply
aTanθ=15°
Divide both sides by Tan 22
aTan22/Tan22 = 15/Tan 22
a = 15/Tan 22°
a = 37.13 m
Therefore the distance between the foot of the cliff to the boat is 37.13 metres
Esmeralda I think it's wrong cuz it’s like the question but that's added a parentheses so I think that's wrong
A supplmentary angle = 180°
∠BDE and ∠BDF are vertical angles, and so are congruent.
∠BDF = 125°, because ∠BDF ≅ ∠BDE.
∠CDA ≅ ∠EDF
∠CDA = 90°
<span>line BJ </span> is angle bisector of ∠CDA. ∠CDB is 1/2 of ∠CDA
∠CDA = 90°
∠CDB = 90/2
∠CDB = 45°
∠GDF is a vertical angle of ∠CDB, and it's measurement will be the same as ∠CDB.
∠GDF ≅ ∠CDB
∠CDB = 45°
∠GDF = 45°
∠GDF = 45° should be your answer
hope this helps
Answer:
If R is equal 5.1, Let x be A/A0
Then we have logx=5.1
Solving this we have x=125893
