Use a let statement
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
-323 -323
x^2 + 2x -323 = 0
third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19
x = -17
hope this help
Answer:
50
Step-by-step explanation:
100 into 2 parts is 50
Answer:
-4 sqrt(7)/7
Step-by-step explanation:
csc theta = -4/3
csc theta = hypotenuse / opposite side
hypotenuse = 4
opposite = 3
Using the pythagorean theorem
a^2 + b^2 = c^2
3^2 + b^2 = 4^2
9+b^2 = 16
b^2 = 16-9
b^2 = 7
Taking the square root
sqrt(b^2) = sqrt(7)
b = sqrt(7)
We are in the third quadrant so only tan and cot are positive
that means the x and y values are "negative" so a = -3 and b = - sqrt(7)
sec theta = hypotenuse / adjacent
= 4/ - sqrt(7)
rationalizing
-4 sqrt(7)/ sqrt(7)* sqrt(7)
= -4 sqrt(7)/7
Answer:
pretty sure its D. 1.6 x 10^9
