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ycow [4]
2 years ago
12

The histogram shows the number of yards gained on first downs. How many times did the team gain at least 6 yards on first downs?

Mathematics
2 answers:
BabaBlast [244]2 years ago
4 0

Answer:

8 times

Step-by-step explanation:

Given

The attached histogram

Required

The number of times the team gain at least 6 yards

From the question, the entry that fall in the category of at least 6 yards are:

6\ to\ 8, 9\ to\ 11 and 12\ to\ 14

Their frequencies are:

5, 2 and 1 respectively

So, the number of times is:

Times = 5 + 2 + 1

Times =8

Rudik [331]2 years ago
3 0

Answer:

Its 8!

Step-by-step explanation:

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lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

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Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

The denominator zeros can be found by factoring:

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Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.

The asymptotes are at the values of x where the denominator is zero:

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3. if y varies directly as x and y=23.1 when x=36.3, find y when x=11.
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Answer:

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Step-by-step explanation:

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