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aksik [14]
2 years ago
13

Write an equation of a line (-4,-1) and is perpendicular to the line y=4/3x+6 y =

Mathematics
1 answer:
NikAS [45]2 years ago
5 0

Answer:

y= -3/4x-2

Step-by-step explanation:

- perpendicular: opposite signs and reciprocal

m= -3/4

point-slope form: y-y1=m(x-x1)

y-(-1)= -3/4(x-(-4))

y+1= -3/4(x+4)

y+1= -3/4x -3

y= -3/4x-2

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If tan0=-3/4 and 0 is in quadrant IV, cos20= (33/25, -17/25, 32/25, 7/25, 24/25?) and tan20= (24/7, -24/7, 7/25, -7/25, 13/7, -1
Oksana_A [137]

Answer:

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Step-by-step explanation:

Sometimes, it is easiest to let a calculator do the work. (See below)

__

The magnitude of the tangent is less than 1, so the reference angle will be less than 45°. Then double the angle will be less than 90°, so will remain in the 4th quadrant, where the cosine is positive and the tangent is negative.

You can also use the identities ...

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__

  tan(2θ) = 2tan(θ)/(1 -tan(θ)²) = 2(-3/4)/((16-9/16) = (-6/4)(16/7)

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